SOLUTION: "How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? With complete solution"

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Question 505204: "How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? With complete solution"
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
"How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? With complete solution"
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Equation:
alcohol + alcohol = alcohol
0.40x + 0.65(20-x) = 0.50*20
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Multiply thru by 100 to get:
40x + 65*20 - 65x = 40*20
-25x = -15*20
x = 12 liters (amt. of 40% solution needed)
20-x = 8 liters (amt. of 65% solution needed)
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Cheers,
Stan H.
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