SOLUTION: Solve the equation for x: 2log base 5 of x + log base 5 of 3 = log base 5(1/125)

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Question 455264: Solve the equation for x: 2log base 5 of x + log base 5 of 3 = log base 5(1/125)
Found 2 solutions by lwsshak3, MathTherapy:
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website!
Solve the equation for x: 2log base 5 of x + log base 5 of 3 = log base 5(1/125)
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2log5(x)+log5(3)=log5(1/125)=log5(5^-3)=-3 (log of the base^x = x)
log5(3x^2) (exponent and multiplication rules)
Convert to exponential form: (base(5) raised to log of number(-3)=number(3x^2)
5^-3=3x^2
x^2=1/125*3
x=1/(5√5*√3)=1/(5√15)
x=√15/75

Answer by MathTherapy(10719) (Show Source):
You can put this solution on YOUR website!

Solve the equation for x: 2log base 5 of x + log base 5 of 3 = log base 5(1/125) The other person's answer, is WRONG!! , with x > 0 OR <==== IGNORE is an ACCEPTED solution, while is NOT, because the LATTER is NOT > 0, but the FORMER is (see constraint above).