SOLUTION: How do you solve the equation on the interval of [0,2pie) in radians? cos^2x+cos2x= 5/4

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Question 435005: How do you solve the equation on the interval of [0,2pie) in radians? cos^2x+cos2x= 5/4
Answer by lwsshak3(11628) About Me  (Show Source):
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How do you solve the equation on the interval of [0,2pie) in radians? cos^2x+cos2x= 5/4
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cos^2x+cos2x= 5/4
2cos^2x=5/4
cos^2x=5/8
cosx=sqrt(5/8)=.79057
arccos(.79057)=.65906
x=.65906 and 5.62094 radians