SOLUTION: Find the solution set in a +bi form: 6x^2 + 4x +1 =0 I need your help please. Thank you very much

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Question 411318: Find the solution set in a +bi form: 6x^2 + 4x +1 =0
I need your help please.
Thank you very much
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the solution set in a +bi form: 6x^2 + 4x +1 =0
..
6x^2 + 4x +1 =0
Use quadratic formula below:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
with a=6,b=4,c=1
..
(-4+-sqrt(4^2-4*6*1))/2*6
=(-4+-sqrt(16-24))/12
=(-4+-sqrt(-8))/12
=(-4+-2*sqrt(-2))/12
=(-4+-2*sqrt(2)i)/12
=(-2+-sqrt(2)i)/6
=-2/6+-(sqrt(2)/6)i)
ans:
-2/6+(sqrt(2)/6)i)
or
-2/6-(sqrt(2)/6)i)