SOLUTION: Hello, Please hep me to solve this problem: Find all exact value solutions [o,360) for sin^2x-2sinx-3 = 0 My work: x^2-2x-3 = 0 sinx = 3 sinx = -1 sin^-1(3) = None sin^-

Algebra ->  Trigonometry-basics -> SOLUTION: Hello, Please hep me to solve this problem: Find all exact value solutions [o,360) for sin^2x-2sinx-3 = 0 My work: x^2-2x-3 = 0 sinx = 3 sinx = -1 sin^-1(3) = None sin^-      Log On


   



Question 390905: Hello,
Please hep me to solve this problem: Find all exact value solutions [o,360) for sin^2x-2sinx-3 = 0
My work:
x^2-2x-3 = 0
sinx = 3
sinx = -1
sin^-1(3) = None
sin^-1(-1) = -90

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
sin^-1(-1) = -90 is actually correct, BUT -90 is not in [0, 360), so the desired solution is -90 + 360 = 270.