SOLUTION: Prove the identity: sin^2 theta/1-cos theta = (sec theta + 1)/sec theta

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Question 370791: Prove the identity: sin^2 theta/1-cos theta = (sec theta + 1)/sec theta
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Prove the identity: sin^2 theta/1-cos theta = (sec theta + 1)/sec theta
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sin^2/(1-cos) = (sec+1)/sec
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Cross multiply to get:
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sin^2*sec = (1-cos)(1+sec)
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sin^2/cos = 1+sec-cos-cos*sec
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sin^2/cos = sec-cos +1-1
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Multiply both sides by cos to get:
sin^2 = 1-cos^2
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sin^2 = sin^2
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Cheers,
Stan H.