SOLUTION: Solve the equation algebraically for "x" where 0&#8804;x<2&#960;. sin2x=cosx Thank you

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Question 359679: Solve the equation algebraically for "x" where 0≤x<2π.
sin2x=cosx
Thank you
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
sin%282x%29=cos%28x%29
.
.
2sin%28x%29cos%28x%29=cos%28x%29
.
.
2sin%28x%29=1
.
.
sin%28x%29=1%2F2
.
.
x=pi%2F6 and x=%285pi%29%2F6