SOLUTION: Hey, I need help finding "x" (b^(2n+1))/(b^n)(b^(4n+3)) = b^x thanks!

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Question 356657: Hey, I need help finding "x"
(b^(2n+1))/(b^n)(b^(4n+3)) = b^x
thanks!
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
%28b%5E%282n%2B1%29%29%2F%28b%5En%29%28b%5E%284n%2B3%29%29+=+b%5Ex
b%5E%282n%2B1%29%2F%28b%5E%28n%2B%284n%2B3%29%29%29+=+b%5Ex
b%5E%282n%2B1%29%2Fb%5E%285n%2B3%29+=+b%5Ex
b%5E%28%282n%2B1%29+-+%285n%2B3%29%29+=+b%5Ex
b%5E%282n%2B1-5n-3%29+=+b%5Ex
b%5E%28-3n-2%29+=+b%5Ex. Therefore,
x+=+-3n-2.