SOLUTION: Solve for x: 3sin^2 x = cos^2 x ; 0 < = x < 2x

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Question 342764: Solve for x:
3sin^2 x = cos^2 x ; 0 < = x < 2x
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
3sin^2 x = cos^2 x ; 0 < = x < 2x (I think you mean < 2pi)
3sin^2(x) = 1 - sin^2(x)
4sin^2 = 1
sin^2 = 1/4
sin(x) = ± 1/2
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x = 30, 150, 210, 330 or
x = pi/6, 5pi/6, 7pi/6, 11pi/6 radians