SOLUTION: Solve the following equation algebraically for all values of theta in the interval 0 degrees is less than or equal to theta which is less than or equal to 180 degrees
2sintheta
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2sintheta
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Question 310722: Solve the following equation algebraically for all values of theta in the interval 0 degrees is less than or equal to theta which is less than or equal to 180 degrees
2sintheta minus 1=0 Found 2 solutions by Fombitz, nyc_function:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! We need to find values for theta (in degrees) that lie between 0 and 180 degrees. We are looking at the first and second quadrants only.
Let t = theta in the equation since I do not have a theta key on the keyboard.
2sin(t) - 1 = 0
Adding 1 to both sides we get:
2sin(t) = 1
Now divide both sides by 2.
sin(t) = 1/2
From the unit circle (that you should memorize), we learn that the values of theta when sine = 1/2 are: 30 degrees and 150 degrees.
NOTE: 30 degrees lies in quadrant 1 and 150 degrees lies in quadrant 2.
