SOLUTION: Find all the solutions in the interval [0, 2pi): sin2x = cos x

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Question 280360: Find all the solutions in the interval [0, 2pi): sin2x = cos x
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find all the solutions in the interval [0, 2pi):
sin(2x) = cos(x)
2sin(x)cos(x) = cos(x)
2sin(x)cos(x) - cos(x) = 0
cos(x)(2sin(x)-1) = 0
cos(x) = 0 or 2sin(x)-1 = 0
cos(x) = 0 or sin(x) = 1/2
x = pi/2 or (3/2)pi or (pi)/6 or (5/6)pi
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Cheers,
Stan H.