SOLUTION: Solve for all values of x: a) 3cosx - 3=cosx-4 b) -4sinx+root2=-2sin x +2 root 2

Algebra ->  Trigonometry-basics -> SOLUTION: Solve for all values of x: a) 3cosx - 3=cosx-4 b) -4sinx+root2=-2sin x +2 root 2      Log On


   

Question 260474: Solve for all values of x:
a) 3cosx - 3=cosx-4
b) -4sinx+root2=-2sin x +2 root 2
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for all values of x:
a) 3%2Acos%28x%29+-+3+=+cos%28x%29-4
step 1 - subtract cosx to get
2cos%28x%29+-+3+=+-4
step 2 - add 3 to get
2cos%28x%29+=+-1
step 3 - divide by 2 to get
cos%28x%29+=+-1%2F2
x = 2pi/3, or 4pi/3.
--
b) -4sinx%2Bsqrt%282%29=-2sinx+%2B2%2Asqrt%282%29
step 1 - add 4 sinx to get
sqrt%282%29+=+2sin%28x%29+%2B2sqrt%282%29
step 2 - subtract 2 sqrt(2) to get
-sqrt%282%29+=+2sin%28x%29
divide by 2 to get
%28-1%2F2%29sqrt%282%29+=+sin%28x%29
x = 3pi/4 and 5pi/4