SOLUTION: solve the equation in the interval [0,2Pi). sin(pi-x)=1

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Question 250620: solve the equation in the interval [0,2Pi). sin(pi-x)=1
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
We start with
sin%28pi-X%29+=+1.
Here is one way. Replace (pi-X) with A.
We have
Sin%28A%29+=+1.
At what values of A is the sin = 1?
A+=+pi%2F2 only.
Substitute (pi-X) back for A and we get
PI-X+=+pi%2F2.
Solving for X, we get
X+=+pi%2F2.