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| Question 218202:  can anyone help me with these question pls....thanks..
 1. From a point due west from the base of the building, the angle of elevation to the top is 65 degrees. At a point 62 meters further, the angle of elevation is 54 degrees. How tall is the building?
 Answer by Theo(13342)
      (Show Source): 
You can put this solution on YOUR website! tan(65) = x/y means x = y*tan(65) tan(54) = x/(y+32) means x = (y+32)*tan(54) = y*tan(54) + 32*tan(54)
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 since they both equal to x, then they are equal to each other, so we get:
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 y*tan(65) = y*tan(54) + 32*tan(54)
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 subtract y*tan(54) from both sides of the equation to get:
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 y*tan(65) - y*tan(54) = 32*tan(54)
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 factor out the y on the left hand side of the equation to get:
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 y*(tan(65)-tan(54)) = 32*tan(54)
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 divide both sides of this equation by (tan(65)-tan(54)) to get:
 y = 32*tan(54) / (tan(65)-tan(54))
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 solve for y to get:
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 y = 57.33991401
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 Since x = y*tan(65), substitute for y to get:
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 x = 57.33991401*tan(65) = 122.9658424
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 height of the building is 122.9658424 meters.
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 since y = 57.33991401, then
 (y+32)*tan(54) = x becomes:
 89.33991401*tan(54) = x = 122.9658424 meters once again.
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 height is confirmed to be true because both points yield the same height.
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 your answer is:
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 height of the building is 122.97 meters rounded to the nearest hundredth of a meter.
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 a picture of your problem can be found by clicking on the following hyperlink.
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 Problem Number 218202 Picture
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