SOLUTION: Solve: 2sin3theta= square root of 2 (for 0 degress < or equal to thetha < or equal to 360 degrees)
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Question 162317
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Solve:
2sin3theta= square root of 2 (for 0 degress < or equal to thetha < or equal to 360 degrees)
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Solve: 2sin3theta= square root of 2 (for 0 degress < or equal to thetha < or equal to 360 degrees)
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2sin(3theta) = sqrt(2)
sin(3theta) = sqrt(2)/2
3theta = 45º, 135º
theta = 15º, 45º