Question 149904: Please help me solve: sin3A=1, o<=A<2pi.
Thank you, Ray
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Please help me solve: sin3A=1, o<=A<2pi.
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sin(3A) = 1
sin(90) = 1 [and sin(450), sin(810), every 360 degrees]
3A = 90, 450, 810
A = 30, 150, 270 within the specified limits
A = PI/6, 5*PI/6, 9*PI/6 (=3*PI/2) in radians
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