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| Question 1204286:  Assume 𝛼 is opposite side a, 𝛽 is opposite side b, and 𝛾 is opposite side c. Solve the triangle, if possible. Round your answers to the nearest tenth. (If not possible, enter IMPOSSIBLE.)
 𝛼 = 36°, 𝛾 = 62°, a = 20
 Found 2 solutions by  math_tutor2020, MathTherapy:
 Answer by math_tutor2020(3817)
      (Show Source): 
You can put this solution on YOUR website! 𝛼 = Greek letter alpha (lowercase)
 𝛽 = Greek letter beta (lowercase)
 𝛾 = Greek letter gamma (lowercase)
 
 𝛼 = 36°
 𝛽 = unknown
 𝛾 = 62°
 
 𝛼 + 𝛽 + 𝛾 = 180
 36 + 𝛽 + 62 = 180
 98 + 𝛽 = 180
 𝛽 = 180 - 98
 𝛽 = 82°
 
 Sides
 a = 20
 b = unknown
 c = unknown
 
 Angles
 𝛼 = 36°
 𝛽 = 82°
 𝛾 = 62°
 
 Law of Sines
 sin(𝛼)/a = sin(𝛽)/b
 sin(36)/20 = sin(82)/b
 b*sin(36) = 20*sin(82)
 b = 20*sin(82)/sin(36)
 b = 33.6948933264092 approximately
 b = 33.7
 Please make sure your calculator is set to degree mode.
 
 Also,
 sin(𝛼)/a = sin(𝛾)/c
 sin(36)/20 = sin(62)/c
 c*sin(36) = 20*sin(62)
 c = 20*sin(62)/sin(36)
 c = 30.0432033439173 approximately
 c = 30.0
 
 
 The fully solved triangle is
 𝛼 = 36°
 𝛽 = 82°
 𝛾 = 62°
 a = 20
 b = 33.7
 c = 30.0
 Diagram
 
  Only one unique triangle is possible due to the AAS congruence theorem.
 
Answer by MathTherapy(10556)
      (Show Source): 
You can put this solution on YOUR website! 
Assume 𝛼 is opposite side a, 𝛽 is opposite side b, and 𝛾 is opposite side c. Solve the triangle, if possible. Round your answers to the nearest tenth. (If not possible, enter IMPOSSIBLE.)
𝛼 = 36°, 𝛾 = 62°, a = 20
With 𝛼, or ∡A being 36°, 𝛾, or ∡C being 62°, then 𝛽, or ∡B = 82° [180° - (36° + 62°)]
Using the Law of sines, we get:  Finding side b (opposite 𝛽), we get:  b * sin (36o) = 20 * sin (82o) ---- Cross-multiplying
                                     Side  Finding side c (opposite 𝛾), we get:  c * sin (36o) = 20 * sin (62o) ---- Cross-multiplying
                                     Side  Only when 2 sides and one angle are given (SSA or ASS: The famous/infamous DONKEY THEOREM), does the AMBIGUOUS case come into effect. The AMBIGUOUS case involves determining whether ONE or TWO triangles can be formed, based on the given 
information. However, when 2 angles and one side are given (AAS or ASA) - as in THIS CASE - then ONLY ONE (1) triangle
can be formed.
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