SOLUTION: One of the legs of a right triangle is twice as long as the other, and the perimeter of the triangle is 28. Find the lengths of all three sides, to three decimal places.

Algebra ->  Trigonometry-basics -> SOLUTION: One of the legs of a right triangle is twice as long as the other, and the perimeter of the triangle is 28. Find the lengths of all three sides, to three decimal places.      Log On


   

Question 1197749: One of the legs of a right triangle is twice as long as the other, and the perimeter of the triangle
is 28. Find the lengths of all three sides, to three decimal places.
Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
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One of the legs of a right triangle is twice as long as the other, and the perimeter of the triangle
is 28. Find the lengths of all three sides, to three decimal places.
~~~~~~~~~~~~~~~~~ 

    x+%2B+2x+%2B+sqrt%28x%5E2%2B%282x%29%5E2%29 = 28

    3x+%2B+sqrt%285%29%2Ax = 28

    x%2A%283%2Bsqrt%285%29%29 = 28

    x = 28%2F%283%2Bsqrt%285%29%29 = 5.348 (rounded)


ANSWER.  The sides are x= 5.348,  2x = 2*5.348 = 10.695,  %28sqrt%285%29%29%2Ax = sqrt%285%29%2A5.348 = 11.957.


CHECK.  5.348 + 10.695 + 11.957 = 28.000.   ! correct !

Solved.