SOLUTION: Find the 3 cube roots of -8 in polar form.

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Question 1180532: Find the 3 cube roots of -8 in polar form.
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Find the 3 cube roots of -8 in polar form.
-8 = -8+0i

Graph the vector whose magnitude (modulus) is r=8, whose tail is at (0,0),
and whose tip is at (-8,0), and whose argument (angle) is θ=180o. 





Since the cube root is the 1/3 power:



We raise everything to the 1/3 power.  In doing so we will use deMoivre's
theorem, where we raise the magnitude (modulus 8) to the 1/3 power (i.e.,
take its cube root 2), and multiply its argument (angle) by 1/3.



Now, since there are 3 cube roots, we take three consecutive integers for n.

Let n=0



Let n=1



Let n=2

.

[Notice that the second one would turn out to be 2(-1+0i) or just -2, which
is the real cube root of -8.]

Edwin

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