SOLUTION: Solve the following equation in the interval [0,2π].Give answer as a multiple of π. |tan(t)|=1 t= π

Algebra ->  Trigonometry-basics -> SOLUTION: Solve the following equation in the interval [0,2π].Give answer as a multiple of π. |tan(t)|=1 t= π      Log On


   

Question 1179777: Solve the following equation in the interval [0,2π].Give answer as a multiple of π.
|tan(t)|=1
t= π
Found 2 solutions by ikleyn, ewatrrr:
Answer by ikleyn(52908) About Me  (Show Source):
You can put this solution on YOUR website!
.

|tan(t)| = 1   means   tan(t) = 1   OR  tan(t) = -1.


For tan(t) = 1,  the solutions are  pi%2F4  and  5pi%2F4.


For tan(t) = -1, the solutions are  3pi%2F4  and  7pi%2F4.


ANSWER.  The full list of solutions is  pi%2F4,  3pi%2F4,  5pi%2F4  and  7pi%2F4.

Solved, answered and explained.


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Regarding the solution by @ewatrrr, notice that it is INCOMPLETE (and therefore incorrect).



Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
tan = sin/cos = 1
If tan= 1 then sin = cos
sin = cos @ π/4 and (5/4)π
(sin,cos) unit wheel
.