SOLUTION: r = 4 cos(6𝜃) Identify zeros of r, 0 ≤ 𝜃 ≤ 2𝜋. Use a graphing utility to verify your results. (Enter your answers as a comma-separated list.)

Algebra ->  Trigonometry-basics -> SOLUTION: r = 4 cos(6𝜃) Identify zeros of r, 0 ≤ 𝜃 ≤ 2𝜋. Use a graphing utility to verify your results. (Enter your answers as a comma-separated list.)      Log On


   



Question 1177441: r = 4 cos(6𝜃)
Identify zeros of r, 0 ≤ 𝜃 ≤ 2𝜋. Use a graphing utility to verify your results. (Enter your answers as a comma-separated list.)

Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

r+=+4cos%286theta%29
Identify zeros of +r,+0+%3C=theta+%3C=+2pi+
To find the zeros, set+r equal to zero and solve for theta.
4cos%286theta%29=0
cos%286theta%29=0
theta=pi%2F12
theta=pi%2F4
theta=5pi%2F12
theta=7pi%2F12
theta=3pi%2F4
theta=1pi%2F12
theta=13pi%2F12
theta=5pi%2F4
theta=17pi%2F12
theta=19pi%2F12
x intercepts:
(pi%2F12,0),(pi%2F4,0),(5pi%2F12,0),(7pi%2F12,0),(3pi%2F4,0),(11pi%2F12,0),(13pi%2F12,0),(5pi%2F4,0),(17pi%2F12,0)


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Answer by greenestamps(13215) About Me  (Show Source):
You can put this solution on YOUR website!


4cos%286%2Atheta%29=0
cos%286%2Atheta%29=0

On the interval 0 to 2pi, cosine theta is 0 twice -- at pi/2 and 3pi/2. Cosine of 6*theta will be 0 6*2=12 times on that interval; the first two zeros will be at (pi/2)/6 and (3pi/2)/6, or pi/12 and 3pi/12. Of course you might want to simplify that second zero to pi/4, but that's not absolutely necessary.

The separation between successive zeros of cosine theta is pi; the separation between zeros of cosine of 6*theta is pi/6 or 2pi/12.

The zeros of 4cos%286%2Atheta%29 on the interval 0 to 2pi:

pi/12, 3pi/12, 5pi/12,..., 19pi/12, 21pi/12, 23pi/12