SOLUTION: \cos A=\frac{5}{13}cosA=
13
5
and \sin B=\frac{12}{37}.sinB=
37
12
. Find the value of \cos(A+B)cos(A+B) in simplest form.
Algebra ->
Trigonometry-basics
-> SOLUTION: \cos A=\frac{5}{13}cosA=
13
5
and \sin B=\frac{12}{37}.sinB=
37
12
. Find the value of \cos(A+B)cos(A+B) in simplest form.
Log On
Question 1173969: \cos A=\frac{5}{13}cosA=
13
5
and \sin B=\frac{12}{37}.sinB=
37
12
. Find the value of \cos(A+B)cos(A+B) in simplest form. Answer by ikleyn(52832) (Show Source):
