SOLUTION: Write the partial fraction decomposition of the following rational expression. {{{ (8x^2+10x+20)/x(x+4)(x+5) }}}

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Question 1162547: Write the partial fraction decomposition of the following rational expression.
+%288x%5E2%2B10x%2B20%29%2Fx%28x%2B4%29%28x%2B5%29+

Found 2 solutions by greenestamps, MathTherapy:
Answer by greenestamps(13258) About Me  (Show Source):
You can put this solution on YOUR website!




Multiply by the least common denominator....

A%28x%2B4%29%28x%2B5%29%2BB%28x%29%28x%2B5%29%2BC%28x%29%28x%2B4%29+=+8x%5E2%2B10x%2B20
A%28x%5E2%2B9x%2B20%29%2BB%28x%5E2%2B5x%29%2BC%28x%5E2%2B4x%29+=+8x%5E2%2B10x%2B20

Equate coefficients:

(1) A%2BB%2BC+=+8
(2) 9A%2B5B%2B4C+=+10
(3) 20A+=+20

Equation (3) immediately gives us A=1. Substituting in (1) and (2) gives us

(4) B%2BC+=+7
(5) 5B%2B4C+=+1

Solve by elimination....

4B%2B4C+=+28
4B%2B5C+=+1
C+=+-27

Then

B+=+34

ANSWER:




Answer by MathTherapy(10587) About Me  (Show Source):
You can put this solution on YOUR website!
Write the partial fraction decomposition of the following rational expression.
+%288x%5E2%2B10x%2B20%29%2Fx%28x%2B4%29%28x%2B5%29+

The other person is WRONG!!

%288x%5E2+%2B+10x+%2B+20%29%2Fx%28x+%2B+4%29%28x+%2B+5%29 = A%2Fx+%2B+B%2F%28x+%2B+4%29+%2B+C%2F%28x+%2B+5%29
%288x%5E2+%2B+10x+%2B+20%29%2Fx%28x+%2B+4%29%28x+%2B+5%29 =  --- Multiplying right-side by LCD, x(x + 4)(x + 5)

 --- Equating NUMERATORS, since DENOMINATORS are same
 ------ Substituting - 5 for x, to determine the value of C
8(25) - 50 + 20 = 0 + 0 + C(- 5)(- 5 + 4)
  200 - 50 + 20 = C(- 5)(- 1)
            170 = 5C
           170%2F5 = 34 = C


 ------ Substituting - 4 for x, to determine the value of B
8(16) - 40 + 20 = 0 + B(- 4)(- 4 + 5) + 0
  128 - 40 + 20 = B(- 4)(1)
            108 = - 4B
          108%2F%28-+4%29 = - 27 = B


 ------ Substituting 1 for x, 34 for C, and - 27 for B, to determine the value of A
8(1) + 10 + 20 = A(5)(6) - 27(1)(6) + 34(1)(5)
   8 + 10 + 20 = 30A - 162 + 170
            38 = 30A + 8
        38 - 8 = 30A
            30 = 30A
           30%2F30%29 = 1 = A

So, (A, B, C)  = (1, - 27, 34)

We then get: highlight%28%288x%5E2+%2B+10x+%2B+20%29%2Fx%28x+%2B+4%29%28x+%2B+5%29%29 = A%2Fx+%2B+B%2F%28x+%2B+4%29+%2B+C%2F%28x+%2B+5%29 = highlight%281%2Fx+%2B+%28-+27%29%2F%28x+%2B+4%29+%2B+34%2F%28x+%2B+5%29%29