SOLUTION: How many different values of x from 0 to 180 degrees for the equation (2sinx-1) (cosx+1)=0?

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Question 1161718: How many different values of x from 0 to 180 degrees for the equation (2sinx-1) (cosx+1)=0?
Answer by ikleyn(52793) About Me  (Show Source):
You can put this solution on YOUR website!
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The linear factor  2*sin(x) - 1 = 0  provides two solutions  x = 30° and x = 150° with sin(x) = 1%2F2.


The linear factor  cos(x) + 1 = 0  provides one additional solutions  x = 180° with cos(x) = -1.


In all, the given equation has 3 solutions in the interval [0,180°].

Solved.