SOLUTION: determine the specified trigonometric ratio for each angle with a terminal side that passes through the given point. 1.Sin0; (-8,6) 2.csc0; (2,-1) 3.tan0;(0,1) 4.cos0; (-4,-

Algebra ->  Trigonometry-basics -> SOLUTION: determine the specified trigonometric ratio for each angle with a terminal side that passes through the given point. 1.Sin0; (-8,6) 2.csc0; (2,-1) 3.tan0;(0,1) 4.cos0; (-4,-      Log On


   



Question 1158028: determine the specified trigonometric ratio for each angle with a terminal side that passes through the given point.
1.Sin0; (-8,6)
2.csc0; (2,-1)
3.tan0;(0,1)
4.cos0; (-4,-2)

Answer by KMST(5377) About Me  (Show Source):
You can put this solution on YOUR website!
The standard position of an angle is vertex at the origin, initial side along the positive x-axis.
We measure angles counterclockwise, and could define an angle measure as negative or greater than 360 degree,
but the trigonometric functions only care about the position of the terminal side.
I will assume 0%5Eo%3C=theta%3C360%5Eo for all angles.

Terminal side passing through P%28-8%2C6%29 :
There is a large right triangles with hypotenuse OP and a similar triangle whose hypotenuse, OA , is a radius of the unit circle shown in red.
The large one has legs of length 8 and 6 , and hypotenuse OP=sqrt%286%5E2%2B8%5E2%29=10 . The length of the small right triangle's hypotenuse, OA=1} ,is 10 times smaller, and so are the legs.
The function sin%28green%28theta%29%29 is defined as the y-coordinate of point A, sin%28green%28theta%29%29=highlight%280.6%29 , and cos%28green%28theta%29%29 is defined as the x-coordinate of point A, cos%28green%28theta%29%29=-0.8 .
We can calculate sin%28red%28alpha%29%29=6%2F10=0.6 as a trigonometric ratio. and determine that red%28alpha%29=36.9%5Eo.
green%28theta%29=180%5Eo-36.9%5Eo=143.1%5Eo
Trigonometric cosine and sine functions of green%28theta%29 , defined as the x-coordinate and the y-coordinate of point A respectively are numerically the same as those for red%28alpha%29 , but may be positive or negative depending on the quadrant.
The sign will be the same for coordinates of any point on the terminal side.

Terminal side passing through P%282%2C-1%29 :
P%282%2C-1%29 is in quadrant IV, with positive x-coordinate, so cos%28theta%29=cos%28alpha%29%3E0.
The large right triangle, in this case, has leg lengths of 2, and 1, and a hypotenuse length of OP=sqrt%282%5E2%2B1%5E3%29=sqrt%284%2B1%29=sqrt%285%29 .
cos%28theta%29=cos%28alpha%29=2%2Fsqrt%285%29 and sec%28theta%29=1%2Fcos%28theta%29=highlight%28sqrt%285%29%2F2=1.118%29(rounded)
The angles involved would be alpha=26.56%5Eo , theta=360%5Eo-26.56%5Eo=333.44%5Eo

Terminal side passing through P%280%2C1%29 :
P is on the unit circle, so its x-coordinate and y-coordinate are cos%28theta%29 and sin%28theta%29 respectively.
cos%28theta%29=0 , sin%28theta%29=1 and tan%28theta%29=sin%28theta%29%2Fcos%28theta%29 is undefined.

Terminal side passing through P%28-4%2C-2%29 :
Booth coordinates are negative, and so will be sine and cosine.
OP would be the hypotenuse of a right triangle with leg lengths 4, and 2.
The hypotenuse length is