SOLUTION: Which equations have a corresponding graph identical to the graph of y=cos(x) A) y=cos(x+((3/2)pi)) B) y=sin(x+(2pi)) C) y=cos((pi/2)-x) D) y=cos(-x) E) y=sin((pi/2)+x) F) y=

Algebra ->  Trigonometry-basics -> SOLUTION: Which equations have a corresponding graph identical to the graph of y=cos(x) A) y=cos(x+((3/2)pi)) B) y=sin(x+(2pi)) C) y=cos((pi/2)-x) D) y=cos(-x) E) y=sin((pi/2)+x) F) y=      Log On


   



Question 1151364: Which equations have a corresponding graph identical to the graph of y=cos(x)
A) y=cos(x+((3/2)pi))
B) y=sin(x+(2pi))
C) y=cos((pi/2)-x)
D) y=cos(-x)
E) y=sin((pi/2)+x)
F) y=sin((pi/2)-x)

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

use identity:
sin%28pi%2F2+%2B+x%29+=+sin%28pi%2F2%29+cos%28x%29+%2B+cos%28pi%2F2%29+sin%28x%29............. sin%28pi%2F2%29+=1 and cos%28pi%2F2%29=0

sin%28pi%2F2+%2B+x%29+=+1%2Acos%28x%29+%2B+0%2A+sin%28x%29

sin%28pi%2F2+%2B+x%29+=+cos%28x%29+


answer is:
E) y=sin%28%28pi%2F2%29%2Bx%29