Question 1149885: the flight from Seattle to New York, with a tailwind, takes 5 hrs 15 min, and the return flight take 6 hrs 35 minutes. Since the flight time includes time to taxi from and to the gate, we should subtract 45 minutes from each time to account for this. Not shown, I was able to find out the plane was scheduled to fly a 2383 mile flight path. Assuming the plane and wind speeds are constant during both flights, estimate the wind speed, to 1 decimal place.
mi/hr
Answer by ikleyn(52848)   (Show Source):
You can put this solution on YOUR website! .
On arrivals, the runway time is the time the plane touches down on the runway. The arrival gate time includes the time it takes
to taxi to the gate. On departures, the gate time is the time at which the plane pulls back from the gate.
https://helpdesk.cirium.com/hc/en-us/articles/217613088-Is-the-arrival-time-runway-time-or-gate-time-What-s-the-difference-
OK. So, under these assumptions, the solution is as follows.
Let u be the average speed of the aircraft at no wind, and let v be the average speed of the wind.
The flight "to there" is 4 hours 30 minute = 4.5 hours in the air.
The flight "back" is 5 hours 50 minute =   =  hours in the air.
u + v =  = 529.555 mph. (The effective speed with the wind)
u - v =  = 408.514 mph (The effective speed against the wind)
From these equations, u, or the plane speed at no wind, is 469.0 mph; ANSWER
v, or the wind speed, is 60.5 mph. ANSWER
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