SOLUTION: two ships p and q left a port r at the same time on different routes.q sailed on a bearing of 150 while p sailed on the north side of q.after a distance of 8km and 10km by p and q

Algebra ->  Trigonometry-basics -> SOLUTION: two ships p and q left a port r at the same time on different routes.q sailed on a bearing of 150 while p sailed on the north side of q.after a distance of 8km and 10km by p and q       Log On


   



Question 1148622: two ships p and q left a port r at the same time on different routes.q sailed on a bearing of 150 while p sailed on the north side of q.after a distance of 8km and 10km by p and q respectively,their distance apart was 12km.find the bearing of p and r.
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
two ships p and q left a port r at the same time on different routes.q sailed on a bearing of 150
while p sailed on the north side of q. after a distance of 8km and 10km by p and q respectively,
their distance apart was 12km.find the bearing of p and r.
~~~~~~~~~~~~~~~~~


My dear visitor,

    the "r" is the port, and the notion/conception of bearing IS NOT APPLICABLE to it . . . 



    Also, the bearings are just GIVEN in the problem, so why do you ask to find them, as if they are not given   ?    ? ?       ? ? ?


The post in whole is a total NONSENSE . . .



Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


P is 8km from R, and Q is 10km from R, and P and Q are 12km apart.

The bearing of Q is given: 150.

The bearing of P is to the north of Q. To find the bearing of Q, we need to subtract angle QRP from Q's bearing of 150.

Use the law of cosines on triangle QRP with side lengths 8, 10, and 12 to find the measure of angle QRP.

12%5E2+=+10%5E2%2B8%5E2-2%288%29%2810%29cos%28x%29
160+cos%28x%29+=+100%2B64-144+=+20
x+=+arccos%281%2F8%29 = 82.82 degrees to 2 decimal places.

ANSWER: The bearing of P is 150-82.82 = 67.18 degrees.