SOLUTION: The following oscilloscope screen
displays the signal generated by the sound of a tuning fork dur-
ing a time span of 5 milliseconds.
The following figure shown on the green
Algebra ->
Trigonometry-basics
-> SOLUTION: The following oscilloscope screen
displays the signal generated by the sound of a tuning fork dur-
ing a time span of 5 milliseconds.
The following figure shown on the green
Log On
Question 1139457: The following oscilloscope screen
displays the signal generated by the sound of a tuning fork dur-
ing a time span of 5 milliseconds.
The following figure shown on the green graph:
https://i.imgur.com/hBff8uL.png
An equation is to be written in the the form of V = a sin bt that models the
signal, where V is in volts and t is in milliseconds. What is the frequency of the sound wave that produced the signal shown above? Answer may be stated in cycles per millisecond.
that's when you're dealing in degrees, which i was.
i wanted to find the frequency when the period for one cycle was 2.5 milliseconds.
that's because the picture you had showed two full cycles in 5 milliseconds.
the formula became frequency = 360 / 2.5 which became frequency = 144.
the graph was sized to show 2 full cycles from x = 0 to x = 5.
the center line of the graph was y = 0.
the range of the equation was y = -2.5 to y = 2.5.
the domain of the equation was x = 0 to x = 5.
i shaded the region of the graph that showed x <= - and x >= 5, so that the focus was from x = 0 to x = 5.
y represented the voltage and x represented the milliseconds.
i could be wrong, but i think the frequency of the sound wave was 2 cycles / 5 milliseconds which resulted in .4 cycles per millisecond.
since there are 1000 milliseconds in a second, that would translate to 400 cycles per second.
this would be the normal way to show the frequency of sound waves, but you wanted cycles per millisecond, so i believe your solution is .4 cycles per millisecond.
https://i.imgur.com/hBff8uL.png 