SOLUTION: Convert -1 + i√3 to polar form.

Algebra ->  Trigonometry-basics -> SOLUTION: Convert -1 + i√3 to polar form.      Log On


   



Question 1138868: Convert -1 + i√3 to polar form.
Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.
The modulus is  sqrt%28%28-1%29%5E2+%2B+%28sqrt%283%29%29%5E2%29 = sqrt%281+%2B+3%29 = sqrt%284%29 = +2.



The given complex number is in QII  with  tan%28alpha%29 = sqrt%283%29%2F%28-1%29 = -sqrt%283%29,  

so the argument  is  alpha = 2pi%2F3 = 120°.



Therefore,  -1+%2B+i%2Asqrt%283%29 = 2%2Acis%282pi%2F3%29%29 = 2*cis(120°).    ANSWER