Let’s prove it using principle of mathematical induction (PMI). P(n)=n^3+2n. For n=1, P(1)=1+2=3 which is divisible by 3. so the base of induction is established. Now for n=k, assume that P(k)=k^3+2k is divisible by 3. Then for n=k+1, P(k+1)=(k+1)^3+2(k+1) = k^3+2k+3k^2+3k+3=P(k)+3(k^2+k+1) Since we assumed P(k) to be divisible by 3, therefore P(k+1) is also divisible by 3. Hence by PMI, n^3+2n is divisible by 3 for any integer positive n.