SOLUTION: simplify the given expressions: a) (2 sin^2α − 1)/(sina + cosa) b) (cos^2a - cot^2a)/(sin^2a - tan^2a) for b i have all the way until (cos^2asin^2a - cos^2a)/(sin^2a) x

Algebra ->  Trigonometry-basics -> SOLUTION: simplify the given expressions: a) (2 sin^2α − 1)/(sina + cosa) b) (cos^2a - cot^2a)/(sin^2a - tan^2a) for b i have all the way until (cos^2asin^2a - cos^2a)/(sin^2a) x       Log On


   

Question 1134376: simplify the given expressions:
a) (2 sin^2α − 1)/(sina + cosa)
b) (cos^2a - cot^2a)/(sin^2a - tan^2a)
for b i have all the way until (cos^2asin^2a - cos^2a)/(sin^2a) x (cos^2a)/(sin^2acos^2a - sin^2a)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

a)
%282sin%5E2%28a%29+-+1%29%2F%28sin%28a%29+%2B+cos%28a%29%29 .......since 1=sin%5E2%28a%29%2Bcos%5E2%28a%29, we have



%282sin%5E2%28a%29+-+sin%5E2%28a%29-cos%5E2%28a%29%29%2F%28sin%28a%29+%2B+cos%28a%29%29

%28sin%5E2%28a%29+-cos%5E2%28a%29%29%2F%28sin%28a%29+%2B+cos%28a%29%29





sin%28a%29+-cos%28a%29


b)

%28cos%5E2%28a%29+-+cot%5E2%28a%29%29%2F%28sin%5E2%28a%29+-+tan%5E2%28a%29%29+

factor both numerator and denominator