SOLUTION: Prove that {{{sin^2(A)<sinA}}}

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Question 1132620: Prove that
sin%5E2%28A%29%3CsinA
Answer by greenestamps(13215) About Me  (Show Source):
You can put this solution on YOUR website!


It's not true; so obviously it can't be proved.

sin^2(A) is always 0 or positive; sin(A) can be negative.

Whenever sin(A) is negative, sin^2(A) is positive and so is greater than sin(A).