SOLUTION: tan^2(theta)-sin^2(theta) / tan^2(theta)sin^2(theta)

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Question 112509: tan^2(theta)-sin^2(theta) / tan^2(theta)sin^2(theta)
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
I presume you want to simplify the expression tan%5E2%28alpha%29-sin%5E2%28alpha%29+%2F+tan%5E2%28alpha%29sin%5E2%28alpha%29. (I'm using alpha because theta doesn't render).

First thing to do is realize that since tan%28alpha%29=sin%28alpha%29%2Fcos%28alpha%29, tan%5E2%28alpha%29=sin%5E2%28alpha%29%2Fcos%5E2%28alpha%29. Now we can write:

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. Factoring out a sin%5E2%28alpha%29

. Because sin%5E2%28alpha%29%2Bcos%5E2%28alpha%29=1, so %281-cos%5E2%28alpha%29%29=sin%5E2%28alpha%29

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Hope that was what you were looking for.
John