SOLUTION: Could someone give me some tips about how to solve this question ? I don't know how to do this question with decimals. Thanks you! Give the smallest two solutions of cos(6θ)

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Question 1117559: Could someone give me some tips about how to solve this question ? I don't know how to do this question with decimals. Thanks you!
Give the smallest two solutions of cos(6θ) = 0.2771 on [ 0,2π ).
Separate the two solutions with a comma.
Be sure to round only once at the end.

Found 2 solutions by math_helper, ikleyn:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Could someone give me some tips about how to solve this question ? I don't know how to do this question with decimals. Thanks you!
Give the smallest two solutions of cos(6θ) = 0.2771 on [ 0,2π ).
Separate the two solutions with a comma.
Be sure to round only once at the end.
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The last sentence needs to specify how many decimal places (which I'd expect to be 4 or less, because the value 0.2771 has 4 signficant digits). I will carry 7 decimal digits for all the calculations and you can round to the required number of digits.

Step-by-step:
+cos%286%2Atheta%29+=+0.2771+
+cos%5E-1%28cos%286%2Atheta%29%29+=+cos%5E-1%280.2771%29+
+6%2Atheta+=+1.2900217+

Now, there are two solutions, the one above (in Q1), and 6%2Atheta+=+2pi+-+1.2900217+ (in Q4).

This is because x is positive in Q1 and Q4, thus +cos%28theta%29+=+x%2Fr+ has positive x in those two quadrants. I am referring to {{ 6* theta }}} here, finding +theta+ itself requires dividing by 6.
Solving the two cases for theta you should get +highlight%28+theta+=+0.2150036+%29 rad for the Q1 angle and +highlight%28+theta+=++0.8321938+%29 rad for the Q4 angle.

A graph might help visualize this, where A and B are the approximate locations of the two solutions:


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EDIT 5/30/18:
In my post, I was referring to the quadrants of +6%2Atheta+ not +theta+ itself. For clarity, let +alpha+=+6%2Atheta then it was +alpha+ in Q1 and Q4. I did mention this fact and I apologize if it was not clear.



Answer by ikleyn(52903) About Me  (Show Source):
You can put this solution on YOUR website!
.
I'd like to make one notice (correction) to the solution by the tutor @Math_helper.


He correctly found one solution  theta_1 = 0.215 radians in Q1.


He also correctly found the other solution  theta_2 = %282pi-0.215%29%2F6 = 0.831 radians,  but mistakenly referred to it as to the angle of Q4.


In fact,  the angle  theta_2 lies in Q1, too.