SOLUTION: Find the equation of the line that passes through points (7,3) and (-2,9)?

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Question 1103884: Find the equation of the line that passes through points (7,3) and (-2,9)?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630) About Me  (Show Source):
Answer by ikleyn(52914) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the equation of the line that passes through points (7,3) and (-2,9)?
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First, calculate the slope.


    The formula for the slope of a straight line passing through two given points    (x%5B1%5D,y%5B1%5D)    and    (x%5B2%5D,y%5B2%5D)    is
        m = %28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29.

    Substitute the given data  x%5B1%5D =7,  y%5B1%5D = 3,  x%5B2%5D = -2, y%5B2%5D = 9  into this basic formula
        m = %289-3%29%2F%28%28-2%29-7%29 = 6%2F%28-9%29 = -2%2F3.


Next, find an equation of the line having the slope 3 and passing through the given point (7,3).


    An equation of a straight line in a coordinate plane which has the slope  m  and passes through the given point  P = (a,b)  is 

        y - b = m*(x-a).     

    Substitute here  m = -2%2F3,  a = 7,  b = 3,  and you will get

        y - 3 = %28-2%2F3%29%2A%28x-7%29.     (*)

    It is the equation in the slope-point form.

    If you want to have it in the general form, transform it in this way

        3y -9 = (-2)*(x-7)   (after multiplying both sides of (*) by 3),   or

        3y -9 = -2x + 14,     and finally

        3y + 2x = 23.

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See the lesson
    - Equation for a straight line in a coordinate plane passing through two given points
in this site.