SOLUTION: For sin a=-3/5 with terminal side in QIII and tan B=-5/12 with terminal side in QIV, find cos(a-B). multiple choice a. -33/65 b. -63/65 c. 63/65 d. 33/65

Algebra ->  Trigonometry-basics -> SOLUTION: For sin a=-3/5 with terminal side in QIII and tan B=-5/12 with terminal side in QIV, find cos(a-B). multiple choice a. -33/65 b. -63/65 c. 63/65 d. 33/65      Log On


   



Question 1087884: For sin a=-3/5 with terminal side in QIII and tan B=-5/12 with terminal side in QIV, find cos(a-B).
multiple choice
a. -33/65
b. -63/65
c. 63/65
d. 33/65

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Draw a picture of the two given angles in their 
respective quadrants.  

Since SINE+=OPPOSITE%2FHYPOTENUSE, make the opposite side
of the angle 'a' nearest the x-axis be the numerator of -3/5,
which is -3, and the hypotenuse be the denominator of -3/5,
which is 5.

Since TANGENT+=OPPOSITE%2FADJACENT, make the opposite side
of the angle 'B' nearest the x-axis be the numerator of -5/12,
which is -5, and the adjacent be the denominator of -5/12,
which is 12.  Use the Pythagorean theorem to calculate the 
adjacent side of angle 'a' to be -4 (negative because it goes
to the left.  Also use the Pythagorean theorem to calculate the 
hypotenuse of angle 'a' to be 13 (positive because the hypotenuse
is the TERMINAL SIDE of the angles which is ALWAYS taken positive.  

    

Now use an identity for 

cos%28a-B%29+=+cos%28a%29cos%28B%29%2Bsin%28a%29sin%28B%29

cos%28a%29=ADJACENT%2FHYPOTENUSE=%28-4%29%2F5=-4%2F5
cos%28B%29=ADJACENT%2FHYPOTENUSE=12%2F13
sin%28a%29=-3%2F5   <--given
sin%28B%29=OPPOSITE%2FHYPOTENUSE=%28-5%29%2F13=-5%2F13

Substitute those values in

cos%28a-B%29+=+cos%28a%29cos%28B%29%2Bsin%28a%29sin%28B%29

and simplify.  You finish.

Edwin