SOLUTION: Please help me find {{{ a }}}, {{{ b }}} & {{{ c }}} for the function {{{f(x)}}}{{{""=""}}}{{{a*sin(bx+c)}}}. The graph of {{{ f }}} must match this graph below. Graph: htt

Algebra ->  Trigonometry-basics -> SOLUTION: Please help me find {{{ a }}}, {{{ b }}} & {{{ c }}} for the function {{{f(x)}}}{{{""=""}}}{{{a*sin(bx+c)}}}. The graph of {{{ f }}} must match this graph below. Graph: htt      Log On


   



Question 1062508: Please help me find +a+, +b+ & +c+ for the function
f%28x%29%22%22=%22%22a%2Asin%28bx%2Bc%29. The graph of +f+ must match this
graph below.
Graph: https://s28.postimg.org/ewgmnyqbh/fig18.png
Thanks.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
.
That's a sine graph shifted left from the origin (0,0)
to the first x-intercept left of the x-axis.

f%28x%29%22%22=%22%22a%2Asin%28bx%2Bc%29

Since the highest it goes in 2, and the lowest it goes is
-2, the amplitude, a, is 2.
So we have so far:

f%28x%29%22%22=%22%222%2Asin%28bx%2Bc%29

The period is given by the formula 2pi%2Fb

Each mark on the x-axis represents π because there
are 6 of them and the 6π at the right end of the graph
lets us know that each mark counts as π.

We can tell the period because it's the distance along
the x-axis from 1 peak to the next.

The peak marked (-π/2,2) has x-coordinate -π/2 and the
next peak is halfway between 3π and 4π which is 3%261%2F2pi, 
or expr%287%2F2%29pi or %287pi%29%2F2. So the period is the 
difference of these two x-values, which is 
%287pi%29%2F2-%28-pi%2F2%29%22%22=%22%228pi%2F2%22%22=%22%224pi

Since the period is given by the formula 2pi%2Fb, we have
the equation:  

2pi%2Fb%22%22=%22%224pi

Multiply both sides by b

2pi%22%22=%22%224pi%2Ab

Divide both sides by 4π

2pi%2F%284pi%29%22%22=%22%22b

Cancel the π's:

2%2F4%22%22=%22%22b

1%2F2%22%22=%22%22b

So we have so far:

f%28x%29%22%22=%22%222%2Asin%28expr%281%2F2%29%2Ax%2Bc%29

Finally we need to know the phase shift which is c%2Fb,
right if it's negative and left if it's positive.

The first x-intercept left of the origin is halfway
between -π and -2π which is -1%261%2F2pi, 
or expr%28-3%2F2%29pi or -%283pi%29%2F2. 

So c = that with a positive sign since it shifts left from (0,0,)

c%2Fb%22%22=%22%22%28%283pi%29%2F2%29%2F2%22%22=%22%22%28%283pi%29%2F2%29%2A%281%2F2%29%22%22=%22%223pi%2F4

So the final answer is

f%28x%29%22%22=%22%222%2Asin%28expr%281%2F2%29%2Ax%2B3pi%2F4%29

Edwin