Question 1042843: Find 2u, -3v, u+v, 3u-4v, for the given vectors u=2i and v=3i-2j
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! u = 2i = 2i+0j = <2,0>
v = 3i-2j = <3,-2>
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2u = 2*<2,0>
2u = <2*2,2*0>
2u = <4,0>
2u = 4i+0j
2u = 4i
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-3v = -3*<3,-2>
-3v = <-3*3,-3*(-2)>
-3v = <-9,6>
-3v = -9i + 6j
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u+v = <2,0> + <3,-2>
u+v = <2+3,0+(-2)>
u+v = <2+3,0-2>
u+v = <5,-2>
u+v = 5i - 2j
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3u - 4v = 3*<2,0> - 4*<3,-2>
3u - 4v = <3*2,3*0> - <4*3,4*(-2)>
3u - 4v = <6,0> - <12,-8>
3u - 4v = <6-12,0-(-8)>
3u - 4v = <6-12,0+8>
3u - 4v = <-6,8>
3u - 4v = -6i + 8j
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