SOLUTION: Please help me solve this equation: Find all real numbers in the interval [0,2pi) that satisfies the equation. cos^2(2x)+sin(2x)=1

Algebra ->  Trigonometry-basics -> SOLUTION: Please help me solve this equation: Find all real numbers in the interval [0,2pi) that satisfies the equation. cos^2(2x)+sin(2x)=1      Log On


   



Question 1030909: Please help me solve this equation:
Find all real numbers in the interval [0,2pi) that satisfies the equation.
cos^2(2x)+sin(2x)=1

Answer by ikleyn(52832) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find all real numbers in the interval [0,2pi) that satisfies the equation.
cos^2(2x)+sin(2x)=1
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Replace cos%5E2%282x%29 by 1+-+sin%5E2%282x%29.

You will get a quadratic equation for sin(2x).

Can you solve this quadratic equation?

Can you complete the task from this point?