SOLUTION: Assume that a is an angle in standard position whose terminal side contains the point (sqrt 6, -sqrt 2). Find the exact values of the 6 trig. functions

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Question 1026266: Assume that a is an angle in standard position whose terminal side contains the point (sqrt 6, -sqrt 2). Find the exact values of the 6 trig. functions
Found 2 solutions by mananth, ikleyn:
Answer by mananth(16949) About Me  (Show Source):
Answer by ikleyn(53742) About Me  (Show Source):
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Assume that a is an angle in standard position whose terminal side contains the point (sqrt(6), -sqrt(2)).
Find the exact values of the 6 trig. functions
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The radius-vector is  r^2 = 6 + 2 = 8;  r  sqrt%288%29 = 2%2Asqrt%282%29.


sin%28theta%29 = y%2Fr = -sqrt%282%29%2F%282%2Asqrt%282%29%29 = -1%2F2.


cos%28theta%29 = x%2Fr = sqrt%286%29%2F%282%2Asqrt%282%29%29 = sqrt%283%29%2F2.


tan%28theta%29 = sin%28theta%29%2Fcos%28theta%29 = -1%2Fsqrt%283%29 = -sqrt%283%29%2F3.


The angle  theta  is  -pi%2F6 = -30 degrees.   Or the same as  theta = 11pi%2F6 = 330 degrees.

Solved.