SOLUTION: Solve the system by addition or substitution. 3x + 6y = 0 x = 2/3 (this is a fraction) The 6y = 0 and x = 2/3 are supposed to be lined up under each other

Algebra ->  Trigonometry-basics -> SOLUTION: Solve the system by addition or substitution. 3x + 6y = 0 x = 2/3 (this is a fraction) The 6y = 0 and x = 2/3 are supposed to be lined up under each other      Log On


   

Question 102510: Solve the system by addition or substitution.
3x + 6y = 0
x = 2/3 (this is a fraction)
The 6y = 0 and
x = 2/3 are supposed to be lined up under each other if this helps anyone, it doesnt help me that is why I need your help.
Thank you.
Found 2 solutions by oberobic, stanbon:
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
3x%2B6y=0
x=2%2F3
Substituting the value 2/3 into the first equation, we have:
3%282%2F3%29%2B6y=0, which simplifies to:
2%2B6y=0.
Subracting 2 from both sides, we have:
6y=-2.
Dividing through by 6:
y=-2%2F6=-1%2F3
Always check. So substitute x=2/3 and y=-1/3 back into the original equation:
3%282%2F3%29%2B6%28-1%2F3%29=2-2=0. Check.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the system by addition or substitution.
3x + 6y = 0
x = 2/3
------------
Substitute to solve for y:
3(2/3) + 6y = 0
2 + 6y = 0
y = -1/3
-------------
Solution: x = 2/3; y = -1/3
===================
Cheers,
Stan H.