SOLUTION: Analyze the function f(x) = sec 2x. Include: - Domain and range - Period and Amplitude - Two Vertical Asymptotes

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Question 1014764: Analyze the function f(x) = sec 2x. Include:
- Domain and range
- Period and Amplitude
- Two Vertical Asymptotes

Answer by ikleyn(52873) About Me  (Show Source):
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Analyze the function f(x) = sec 2x. Include:
- Domain and range
- Period and Amplitude
- Two Vertical Asymptotes
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f(x) = sec(2x) = 1%2Fcos%282x%29.

The domain is all number line (all real numbers) except those where cos(2x) = 0.

These exceptional values are 2x = pi%2F2+%2B+k%2Api, k = 0, =/-1, +/-2, . . .
In other words, the exceptional values for x are pi%2F4+%2B+k%2A%28pi%2F2%29, k = 0, =/-1, +/-2, . . .

The range is the union of two infinite intervals: y <= -1 and y >=1.

The period is the same as for the function cos(2x), i.e. pi.

There is no amplitude. The conception/notion of an amplitude is not applicable to the function y = sec(2x).

Vertical asymptotes are there where cos(2x) = 0, i.e. at the points pi%2F4+%2B+k%2A%28pi%2F2%29, k = 0, =/-1, +/-2, . . . - the same exceptional points mentioned above.

Plot of the function y = sec(2x) is shown below.



Figure. Plot y = sec(2x)