SOLUTION: Prove that {{{ ( sec8A - 1)/sec4A}}}={{{Tan8A/tan2A}}}
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-> SOLUTION: Prove that {{{ ( sec8A - 1)/sec4A}}}={{{Tan8A/tan2A}}}
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Question 1014705
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Prove that
=
Answer by
robertb(5830)
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Making use of an ordinary scientific calculator, it can be verified that this trigonometric expression is NOT an identity.