SOLUTION: If sin(&#952;)= sqrt 70 14 and 0°<&#952;<90°, what is cos(&#952;)?

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Question 1008691: If sin(θ)=
sqrt 70
14
and 0°<θ<90°, what is cos(θ)?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If sin(θ)=
sqrt 70
14
and 0°<θ<90°, what is cos(θ)?
-----
By definition, sin = y/r.
So, y = sqrt(70) and r = 14
--
Then x = sqrt[14^2-(sqrt(70))^2] = sqrt(196-70) = sqrt(126) = sqrt(9*14)
= 3sqrt(14)
----
Ans: cos(t) = x/r = 3sqrt(14)/70
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Cheers,
Stan H.
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