Start with the formula of triple argument for sine:

sin(3x) = -4*sin^3(x) + 3*sin(x)

(see,  for example,  the lesson  Trigonometric functions of multiply argument  in this site).

It gives you an equation 

-4*sin^3(x) + 3*sin(x) = sin(x).

Move the term sin(x) from the right side to the left with the opposite sign and then simplify.

-4*sin^3(x) + 3*sin(x) - sin(x) = 0,

-4*sin^3(x) + 2*sin(x) = 0.

Now factor the left side

 = .   (1)

In this way the equation (1) decomposes in two equations. One is

sin(x) = 0 with the solutions x = 0, +/-, +/-, +/-, . . . , +/-, . . . (2)

The other equation is 

 = ,   or

sin(x) = +/- .          

It has the roots x = +/- .   (3)

So, the answer is the combination (the union) of solutions (2) and (3).

x = +/- {k*pi}}}, k = 0, 1, 2, 3, . . .  and

x = +/- , k = 0, 1, 2, 3, . . . 

Obviously, the last set overlay the previous one, so you may restrict yourself by the last formula.