Tutors Answer Your Questions about Triangles (FREE)
Question 810599: Find are of Triangle STU. It is a right triangle, I don't know how to do that on here. But the 'height' is missing, the hypotenuse is 12, and the base is 4. I did a^2 + 4^2 = 12^2 and get a^2 + 16=144
So 144-16=128
a^2=128
is which is 8 . But 8*4 is 32 and the answer key says it's 16
Click here to see answer by Okeke_Christian(26)  |
Question 810599: Find are of Triangle STU. It is a right triangle, I don't know how to do that on here. But the 'height' is missing, the hypotenuse is 12, and the base is 4. I did a^2 + 4^2 = 12^2 and get a^2 + 16=144
So 144-16=128
a^2=128
is which is 8 . But 8*4 is 32 and the answer key says it's 16
Click here to see answer by MathLover1(20849)  |
Question 812125: MY PROBLEM: please help me solve this Question..... The perimeter of a triangle is 25 inches. The first side is 6 inches longer than the second side. The third side is 5 inches shorter than the second side. Find the length of each side.
MY EFFORT: 2L+b=25
L=6+b 2(6+b)+b=25
12+3b=25
-12 -12
3b= 13
B= ??????
Click here to see answer by erica65404(394)  |
Question 812511: The perimeter of a triangle is 60 meters. The length of one side is 6 meters less than twice the length of the shortest side. The length of another side is three times the length of the shortest side. What are the lengths of the three sides?
Click here to see answer by richwmiller(17219)  |
Question 812801: I have a right-angle triangle with a hypotenuse of 4.6cm and an area of 2cm. I need to calculate the lengths of the other two sides. I can see the product of the unknown sides is 4, but is there a formula to calculate the ratio of the sides and therefore the lengths?
Click here to see answer by richwmiller(17219)  |
Question 813259: Hi there! Kindly guide me on following matter.
I am 5.9" tall and standing at ground. I am seeing a bird sitting at the top of the building (i don't know the height of building).
The distance between my eyes and bird is 35yards. (i determine it by using range finder).
But i don't know the distance between me and base of the building at the ground.
At which angle i am seeing that bird?
Your kind guidance in this regard will be highly appriciated.
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 813540: Three circles with centers A, B, and C are externally tangent to each other as shown in the figure. Lines EG and DG are tangent to circle C at point F and D and intersect at point G. If each circle has a diameter of 6 inches, find the length of DG and the area enclosed by lines FG and GD and arc FD.
Click here to see answer by Alan3354(69443)  |
Question 813681: The legs of a right triangle are 4 cm and x cm. The hypotenuse is (2x-1) cm. What is x? I know the answer to this question is 3 but what I can't figure out is how that solution was achieved. I tried setting up the equation like but got the wrong answer. Can you help?
Click here to see answer by Alan3354(69443)  |
Question 813681: The legs of a right triangle are 4 cm and x cm. The hypotenuse is (2x-1) cm. What is x? I know the answer to this question is 3 but what I can't figure out is how that solution was achieved. I tried setting up the equation like but got the wrong answer. Can you help?
Click here to see answer by ewatrrr(24785)  |
Question 813681: The legs of a right triangle are 4 cm and x cm. The hypotenuse is (2x-1) cm. What is x? I know the answer to this question is 3 but what I can't figure out is how that solution was achieved. I tried setting up the equation like but got the wrong answer. Can you help?
Click here to see answer by stanbon(75887) |
Question 813687: The legs of a right triangle are 4 cm and x cm. The hypotenuse is (2x-1) cm. What is x? I know the answer to this question is 3 but what I can't figure out is how that solution was achieved. I tried setting up the equation like but got the wrong answer. Can you help?
Click here to see answer by stanbon(75887) |
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