SOLUTION: A community wants to build a baseball diamond . The available space is limited. So the distance from home plate to second base will be 100 feet. What will be the distance x betwee

Algebra ->  Triangles -> SOLUTION: A community wants to build a baseball diamond . The available space is limited. So the distance from home plate to second base will be 100 feet. What will be the distance x betwee      Log On


   



Question 976295: A community wants to build a baseball diamond . The available space is limited. So the distance from home plate to second base will be 100 feet. What will be the distance x between bases to the nearest foot?
Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
Home to second base is opposite corners of a square.
If the diagonal of he square is 100, the side is 100/(sqr(2)) = 70.7