SOLUTION: In triangle ABC, side AB = x, angle B = 70 degrees, and side BC = y.
In triangle PQR, side PQ = x, angle Q = 110 degrees, and side QR = y.
The area of ABC is 30. What is the a
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-> SOLUTION: In triangle ABC, side AB = x, angle B = 70 degrees, and side BC = y.
In triangle PQR, side PQ = x, angle Q = 110 degrees, and side QR = y.
The area of ABC is 30. What is the a
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Question 973150: In triangle ABC, side AB = x, angle B = 70 degrees, and side BC = y.
In triangle PQR, side PQ = x, angle Q = 110 degrees, and side QR = y.
The area of ABC is 30. What is the area of PQR?
The answer is given as 30.
I can see that the two angles are opposites of each other, but as these aren't right triangles, or similar triangles, how do you prove that the areas are the same. What theorem is this based on?
Thank you.
Helen Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Area = b*h/2
h = side x or y times cos of the angle
cos(70) = cos(110)
--> same h, same area.
