SOLUTION: find the area of the isosceles triangle with side lengths 14 inches,25 inches,and 25inches

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Question 944858: find the area of the isosceles triangle with side lengths 14 inches,25 inches,and 25inches
Found 2 solutions by Fombitz, Alan3354:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Using Heron's formula,
s=%281%2F2%29%2814%2B25%2B25%29=%281%2F2%29%2864%29=32
So then,
A=sqrt%2832%2832-14%29%2832-25%29%2832-25%29%29
A=sqrt%2832%2818%29%287%29%287%29%29
A=24%2A7
A=168in%5E2

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
find the area of the isosceles triangle with side lengths 14 inches,25 inches,and 25inches
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An isoceles triangle can always be made into 2 congruent right triangles with an altitude from the vertex of the 2 equal sides to the 3rd side.
In this case, it makes two right triangles with sides of 7, 24 & 25.
Area of each = b*h/2 = 7*24/1 = 84 sq inches
Total area = 168 sq inches.